4.1
Graph Quadratic Functions in Standard Form
Quadratic function
A
function that can be written in the standard form y = ax2
+ bx+ c where a ¹ 0
Parabola
The
U-shaped graph of a quadratic function
Vertex
The
lowest or highest point on a parabola
Axis of symmetry
The
vertical line that divides the parabola into mirror images and passes through
the vertex
Minimum and maximum value
For
y= ax2 + bx+ c, the vertex's y-coordinate is
the minimum value of the function if
a > 0 and its maximum value
if a < 0.
PARENT
FUNCTION FOR QUADRATIC FUNCTIONS
The lowest or highest point on a parabola is
the vertex for The
axis of symmetry divides the parabola into mirror images and passes through
the vertex
f(x) = x2 is (0,0)
The parent function for
the family of all quadratic functions is f(x) = __x2__ .
The graph is shown below
For
f(x) = ax2, and for any quadratic
function g(x)= ax2 +
bx + c where b = 0, the vertex lies on the __y-axis__
and the axis of symmetry is x = _0_.

Example
1
Graph
a function of the form y = ax2 + c
Graph
y = -2x2 +
2. Compare the graph with the graph of y = x2.
Solution
1.
Make a table of values for y
= -2x2 +
2.
|
x |
-2 |
-1 |
0 |
1 |
2 |
|
y |
_-6_ |
_0_ |
_2_ |
_0_ |
_-6_ |
Choose
values of x on both sides of the axis of symmetry
x = 0.
2.
Plot the points from the
table.
3.
Draw a smooth __curve__
through the points.

4.
Compare the graphs of y
= -2x2 +
2 and y = x2. Both graphs have the same __axis of
symmetry__. However, the graph of y = -2x2
+ 2 opens _down_ and is _narrower_ than the graph of y = x2.
Also, its vertex is _2_units higher.
PROPERTIES OF THE GRAPH OF y = ax2
+ bx + c
Characteristics
of the graph of y = ax2 + bx + c:
·
The graph opens up if a _>_ 0 and opens down if a
_<_ 0.
·
![]()
The graph is narrower
than the graph of y = x2 if | a | _>_ 1 and wider if | a
| _<_ 1.
·
![]()
The axis of symmetry is x = and the vertex has x-coordinate .
·
The y-intercept is _c_. So,
the point (0, _c_) is on the parabola.
Example
2
Graph
a function of the form y = ax2 + bx + c
Graph
y = -x2 + 4x - 3.
Solution
1.
Identify the coefficients of the
function. The coefficients are a = _-1_, b = _4_,
and
c = _-3_. Because a _<_ 0, the parabola opens
_down_.
2.
Find the vertex. First,
calculate the x-coordinate.
Be
sure to include the negative sign before the fraction when calculating the x-coordinate
of the vertex.
![]()
![]()
x
= = =
_2_
Then find the y-coordinate.
y = __-(2)2 + 4(2) - 3__ = _1_
The vertex is (_2_,
_1_). Plot this point.
3.
Draw the axis of symmetry x
= _2_.
4.
Identify the y-intercept c,
which is _-3_.
Plot the point (0, _-3_). Then reflect this
point in the axis of symmetry to plot another point (4, _-3_).
5.
Evaluate the function for
another value of x, such as x = 1.
y = __-(1)2 + 4(1) - 3__ = _0_
Plot the point (1, _0_)
and its reflection (3, _0_) in the axis of symmetry.
6.
Draw a parabola through the
plotted points.
MINIMUM AND MAXIMUM VALUES

Words For y = ax2
+ bx + c, the vertex's y-coordinate is the minimum value
of the function if a _>_
0 and the maximum value if a _<_
0.
Example
3
Find
the minimum or maximum value
Tell
whether the function y = -3x2
+ 12x - 6 has a minimum
value or a maximum value. Then find the minimum or maximum value.
Solution
![]()
Because a _<_ 0, the function has a __maximum__
value. To find it, calculate the coordinates of the vertex.
x = = = _2_
y = __-3(2)2
+ 12(2) - 6__ = _6_
The
maximum value is y = _6_ .