1.7 Solve Absolute Value Equations and Inequalities

 

 

Absolute value

The absolute value of a number x, written | x|, is the distance the number is from 0 on a number line.

 

Extraneous solution

An apparent solution that must be rejected because it does not satisfy the original equation.

 

 

INTERPRETING ABSOLUTE VALUE EQUATIONS

Equation        |x| = |x - 0| = k

Meaning           The distance between x and 0 is __k__ .

Graph              

Solutions         x - 0 = -k or x - 0 = k

                       x = _-k_ or x = _k_

Equation           |x - b| = k

 

Meaning           The distance between x and b is _k_.

 


Graph              

Solutions         x - b = -k or x- b = k

x = _b - k_ or x = _b + k_

 

Example 1

Solve a simple absolute value equation

 

Solve |x - 3 | = 6. Graph the solution.

|x - 3| = 6                                                    Write original equation.

x - 3 = _-6_ or x - 3 = _6_                     Write equivalent equations.

x = _3 - 6_ or   x = _3 + 6_               Solve for x.

x = _-3_ or       x = _9_                      Simplify.

The solutions are _-3_ and _9_ .These are the values of x that are _6_ units away from _3_ on a number line.

 

 


Solve the equation. Then graph the solution.

1.   |x|= 5                                            x = -5 or x = 5

 


2.   |x - 5| = 2                                     x = 3 or x = 7

 

 


SOLVING AN ABSOLUTE VALUE EQUATION

Use these steps to solve an absolute value equation | a + b | = c where c > 0.

Step 1 Write two equations: ax + b = _c_ or ax + b = _- c__ .

Step 2 _Solve_ each equation.

Step 3 Check each solution in the original _absolute value_ equation.

 

Example 2

Solve an absolute value equation

 

Solve |4x + 10 | = 6x. Check for extraneous solutions.

|4x + 10 | = 6x                                                Write original equation.

4x + 10 = _6x_ or     4x + 10 = _-6x_        Expression can equal _6x_ or _-6x_ .

10 = _2x_ or              10 = _-10x_      Subtract _4x_ from each side.

_5_ = x       or             _-1_ = x            Solve for x.

Check the apparent solutions to see if either is extraneous.

 

CHECK

|4x + 10 | = 6x                          |4x + 10 | = 6x

|4(_5_) + 10| 6(_5_)          |4( -1_ ) + 10 | 6(_-1_)

|_30_| _30_                             |_6_| _-6_

_30_ = _30_                               _6_ ¹ _-6_

Text Box: Always check your solutions in the original equation to make sure that they are not extraneous.

The solution is _5_. Reject _-1_ because it is an _extraneous_ solution.

 

 

Solve the equation. Check for extraneous solutions.

3.     |2x + 5| = 11

x = 3 and x = -8

4.      |3x + 18| = 6x

x = 6; x = -2 is an extraneous solution.

 

ABSOLUTE VALUE INEQUALITIES

In the inequalities below, c > 0.

Inequality            Equivalent Form                         Graph of Solution

Text Box: In the inequalities shown at the right, £ can replace < and ³ can replace > and the graphs would have solid dots.

|ax + b| _<_ c       -c < ax + b < c

 

|ax + b| _>_ c       ax + b < -c or ax + b > c

 

 

Example 3

Solve an inequality of the form |ax + b| > c

 

Solve |2x + 5 | > 3. Then graph the solution.

The absolute value inequality is equivalent to 2x + 5 < _-3_ or 2x + 5 > _3_ .

First Inequality                                                     Second Inequality

 

2x + 5 < _-3_       Write inequalities.                     2x + 5 > _3_

2x < _-8_        Subtract _5_ from each side.          2x > _-2_

2x < _-4_        Divide each side by _2_ .                 x > _-1_

The solutions are all real numbers less than _-4_ or greater than _-1_.

 

 


Example 4

Solve an inequality of the form | ax + b | £ c

 

Solve |x - 1.5| £ 4.5. Then graph the solution.

x - 1.5 £ 4.5                         Write inequality.

_-4.5_ £ x - 1.5 £ _4.5_     Write equivalent compound inequality.

_-3.0_ £ x £ _6.0_                Add _1.5_ to each expression.

 

 

The solution is between _-3_ and _6_ , inclusive.

 

 


Solve the inequality. Then graph the solution.

5.      |x - 2| ³ 7                                                  x £ -5 or x ³ 9

 


6.     |4x - 1| < 9                                                 -2 < x < 2.5